Example sentences of "by pivoting in the " in BNC.
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| 1 | When θ = ⅕ , ¼ - 1¼ θ = 0 , indicating an alternative optimal solution ( Section 3.5 ) , which can be found by pivoting in the s 1 -column . |
| 2 | For θ = 3 in P1/T3 , an alternative optimal tableau is found by pivoting in the s 2 -column . |
| 3 | If the partner of σ J ( or x J ) is basic ( as in P2/T3 ) , it is readily verified ( see Exercise 3 ) that the next tableau can also be obtained by pivoting in the row containing the partner of σ J ( or x J ) and the same pivot column , and multiplying the new pivot column by -1 . |
| 4 | This is equivalent to obtaining one tableau from the other by pivoting in the jth column while ( 9.8 ) has a non-negative solution with . |
| 5 | Developing node 6 means increasing the lower bound on x , from 4 to 5 in problem 3 and this is achieved by pivoting in the x 1 -row in P1/LP3 . |
| 6 | This is achieved by pivoting in the -row of P1*/LP0 to get P1 /LP1 . |
| 7 | We therefore solve LP6 by pivoting in the x 2 -row of P1*/LP3 and find an optimal tableau with integer BFS ( x 1 , x 2 , x 3 ) = ( 3 , 1 , 1 ) and objective function value 20 . |