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has [be] [vb pp] from the [num]

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No Pattern Freq Relations
1 has [be] [vb pp] from the [num] 5                    
2 has [been] [vb pp] from the [num] 5                    
3 has been [vb pp] from the [num] 5                    
4 has [be] [vb pp] from the [num] 5                    
5 has be [vb pp] from the [num] 5                    
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